West Bengal Board Class 10 Math Book Solution In English Chapter 4 Rectangular Parallelopiped or Cuboid Exercise 4.1
Application 1. I am observing that the length, breadth, and height of the rectangular parallelopiped box, brought by my brother, are 40 cm, 25 cm, and 15 cm respectively.
Solution: Total surface area of a rectangular box
=2 (LxB+ L x H + B x H)
=2 (40 x 25+ 40 x 15+ 25 x 15) sqcm.
=2 (1000+ 600 + 375) sqcm.
= 2 x 1975 sqcm.
= 3950 sqcm. Ans.
Read and Learn More WBBSE Solutions For Class 10 Maths
Application 2. The length, breadth, and height of a rectangular parallelopiped box are 15 cm, 12 cm, and 20 cm respectively. Let me write its total surface area.
Solution: Total Surface area of a rectangular parallelopiped
=2 (15 x 12 + 15 x 20 + 12 x 20) sqcm.
=2 (180 + 300 +240) sqcm = 2 x (720) sqcm
= 1440 sqcm. Ans.
Application 3. By measuring, I see that the length of one side of the cube, brought by Rajia is 27 cm.
Application 4. Let us write by calculating the number of colored papers required to cover the whole surface of a cube whose length of one side is 12 cm.
Application 5. The length, breadth, and height of our living room are 7 m, 5 m, and 4 m respectively. The shape of the room is
[cube/rectangular parallelopiped] Let us calculate the total area to color four walls of the room.
Application 6. Let us write the length of one side of a cube whose total surface area is 150 sq. cm.
Application 7. Let us calculate the length of one side of a cube whose total surface area is 486 sq.m.
wbbse class 10 maths chapter 4 exercise 4.1
Application 8. A cuboidal room has its length, breadth, and height as a, b, and c units respectively and if a + b + c = 25 units, ab + bc + ca= 240.5 units, then let us write the length of the longest rod that can be kept in this room.
WBBSE Solutions Guide Class 10 Application 9. I have made a rectangular parallelopiped by joining two cubes side by side made by Mita, whose edge is 8 cm in length. Let us calculate the total surface area and the length of the diagonal of the rectangular parallelopiped which is made in this way.
Application 10. By measuring the cuboidal box, I am observing that the length is 32 cm, breadth is 21 cm, and height is 15 cm.
Solution: Volume of the sand = 32 x 21 x 15 cu. cm = 10080 cu. cm.
Application 11. The length of one side of a cube is 5 cm and its volume is c.c = c.c
wbbse class 10 maths chapter 4 exercise 4.1
Application 12. If the length, breadth, and volume of a cuboidal room are 8 m, 6 m, and 192 cubic m respectively, then let us calculate the height of the room and the area of the four walls of the room.
wbbse class 10 maths chapter 4 exercise 4.1
Application 13. The length and breadth of cuboidal water land in the neighboring villages are 18 m and 11 m respectively. In this water land, water is being irrigated from a nearby pond with a pump. If the pump can irrigate 39,600 lit. water per hour then for how much time is required to raise the height of the water level by 3.5 cm of the water land [1 lit. – 1 cubic DCM.]
Application 14. If the pump can fill 37,400 lit. water in 1 hour, then what time will be required to raise the height of water 17 dcm of a cuboidal water land whose length is 18 m and breadth is 11 m. Let us write by calculating it.
WBBSE Solutions Guide Class 10 Application 15. From a wooden log with a length of 5 cm., a breadth of 5 dcm. and the thickness of 3 cm, 40 planks are 2 cm in length and 2 cm in breadth are cloven. For cleaving, wood has been destroyed. But still now 108 cubic dcm of wood remains in the log. What is the thickness of each plank that is cloven.
