NEET Physics Communication Systems Notes

NEET Physics Communication Systems Notes

Communication Systems

  • Communication is the act of transmission of information.
  • Every communication system has three essential elements transmitter, medium/channel, and receiver.
  • There are two basic modes of communication:
    1. Point to point
    2. Broadcast

Satellite Communication and its Applications NEET Questions

Basic Terminology Used in Communication Systems

 

NEET Physics Communication Systems Notes

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  • A repeater is a combination of a receiver and a transmitter.
  • The frequency range of speech signals 300Hz to 3100Hz
  • Bandwidth of speech signals = (3100 – 300)Hz = 2800Hz
  • The audible range of frequencies extends from 20Hz to 20kHz.
  • To radiate signals with very high efficiency the antennas should have a size at least \(\frac{\lambda}{4}\)
  • The attenuation of ground waves increases very rapidly with an increase in frequency
  • From a few MHz to 30MHz, long-distance communication is made possible using ionospheric reflection.
  • E.M. waves of frequencies greater than 30MHz penetrate the atmosphere and go to space. Hence they can be used in space wave propagation or line of sight communication (LOS).

Radio Horizon of the Transmitting Antenna

NEET Physics Communication Systems Important Questions

\(\mathrm{d}_{\mathrm{T}}=\sqrt{2 \mathrm{Rh}_{\mathrm{T}}}\)

Maximum line of sight distance between two antennas having heights hT and hR above the earth is given by,

\(\mathrm{d}_{\mathrm{M}}=\sqrt{2 \mathrm{Rh}_{\mathrm{T}}}+\sqrt{2 \mathrm{Rh}_{\mathrm{R}}}\)

The power radiated by the antenna is proportional to

\(\mathrm{P} \propto \frac{1}{\lambda^2}\)

Communication Systems NCERT Summary for NEET

Amplitude modulation: The process of varying the amplitude of the carrier wave according to the variations of the modulating signal, without changing the frequency and phase of the carrier is called amplitude modulation.

Carrier wave,

\(c(t)=A_c \sin \left(\omega_c t\right)\)

Modulating signal,

\(m(t)=A_m \sin \left(\omega_m t\right)\)

Modulated wave,

\(c_m(t)=\left(A_c+A_m \sin \omega_m t\right) \sin \omega_c t\) \(c_m(t)=A_c\left(1+\frac{A_m}{A_c} \sin \omega_m t\right) \sin \omega_c t\) \(c_m(t)=A_c \sin \omega_c t+\frac{\mu A_c}{2} \cos \left(\omega_c-\omega_m\right) t-\frac{\mu A_c}{2} \cos \left(\omega_c+\omega_m\right) t\)

where,

Concept of Signal Bandwidth and Noise in Communication Systems

\(\omega_{\mathrm{c}}-\omega_{\mathrm{m}}\) is called lower side band frequency.

\(\omega_c+\omega_m\) is called upper side band frequency.

\(\mu=\frac{A_m}{A_c}\) is called modulation index.

The difference in upper sideband frequency (USB) and lower sideband frequency (LSB) is called bandwidth.

\(
\text { i.e., } \mathrm{B} \cdot \mathrm{W}=\left(\omega_{\mathrm{c}}+\omega_{\mathrm{m}}\right)-\left(\omega_c-\omega_{\mathrm{m}}\right)
B. W=2 \omega_{\mathrm{m}}\)

NEET Physics Semiconductor Electronics Notes

NEET Physics Semiconductor Electronics Notes

Semiconductor Electronics

If a p.d. is applied across an intrinsic semiconductor the current I = Ie + Ih

Where Ie is the current due to electrons and I is the current due to holes

  • For semiconductors (Eg < 3eV)
  • \(\left(\mathrm{E}_{\mathrm{g}}\right)_{\mathrm{Ge}}=0.71 \mathrm{eV},\left(\mathrm{E}_{\mathrm{g}}\right)_{\mathrm{Si}}=1.1 \mathrm{eV}\)
  • For insulators, Eg > 3eV
  • In an intrinsic semiconductor \(n_e=n_h\)
  • In n–type semiconductor \(n_e \gg>n_h\)
  • In p–type semiconductor \(n_h \gg n_e\)
  • In an extrinsic semiconductor,
\(\mathrm{n}_{\mathrm{e}} \mathrm{n}_{\mathrm{h}}=\mathrm{n}_{\mathrm{i}}^2\)
  • Where ni = intrinsic carrier concentration.

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  • In a pn junction,
    With of depletion region \(\propto \frac{1}{\text { Doping }}\)
  • The current gain in the CB mode of a transistor is given by
\(\alpha_{d c}=\frac{I_c}{I_E}\)
  • The current amplification factor is
\(\alpha_{\mathrm{ac}}=\left(\frac{\Delta \mathrm{I}_{\mathrm{c}}}{\Delta \mathrm{I}_{\mathrm{B}}}\right)_{\mathrm{V}_{\mathrm{CB}}=\text { constant }}\)
  • The current gain in CE mode is given by,
\(\beta_{\mathrm{dk}}=\frac{\mathrm{I}_{\mathrm{c}}}{\mathrm{I}_{\mathrm{B}}}\)

NEET Physics Semiconductor Electronics Notes

  • The current amplification factor is given by
\(\beta_{x c}=\left(\frac{\Delta I_c}{\Delta I_B}\right)_{V_{C S-c o c e t a n t}}\)
  • w.k.t., IE = Ic + IB
\(\frac{I_E}{I_C}=1+\frac{I_B}{I_C}\) \(\Rightarrow \frac{1}{\alpha_{\mathrm{de}}}=1+\frac{1}{\beta_{\mathrm{de}}}=\frac{\beta_{\mathrm{de}}+1}{\beta_{\mathrm{de}}}\) \(\Rightarrow \frac{1}{\alpha_{\mathrm{dc}}}-1=\frac{1}{\beta_{\mathrm{dc}}}=\frac{1-\alpha_{\mathrm{dc}}}{\alpha_{\mathrm{dc}}}\) \(\begin{array}{r}
\alpha_{\mathrm{dc}}=\frac{\beta_{\mathrm{dc}}}{\beta_{\mathrm{dc}}+1} \\
\Rightarrow \beta_{\mathrm{dc}}=\frac{\alpha_{\mathrm{de}}}{1-\alpha_{\mathrm{de}}}
\end{array}\)

NEET Physics Semiconductor Electronics Important Formulas

  • Voltage gain in an amplifier,
\(A_v=\frac{V_0}{V_i}=-\frac{R_L \Delta I_C}{r \Delta I_B}\)

Where RL is loud resistance,

r is the input resistance

\(A_V=-\frac{\beta_{x c} R_L}{r}\)

Power gain = \(\mathrm{A}_V \times \mathrm{A}_1\)

\(=A_V \times \beta_x=-\frac{\beta_{x c}^2 R_L}{r}\)

OR

\(A_V=\frac{I_C R_o}{I_B R_i}=\beta \frac{R_0}{R_i}\) \(A_P=\beta^2 \frac{R_0}{R_i}\)

where Ro and Ri are the output and input resistances respectively.

NEET Physics Semiconductor Electronics Notes

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OR Gate

NEET Physics Semiconductor Electronics OR Gate

AND Gate

NEET Physics Semiconductor Electronics AND Gate

Semiconductor Electronics NEET Important Questions and Answers

Note:

  • OR gate is equivalent to the parallel switching circuit
  • AND gate is equivalent to the series switching circuit

NOT Gate

NEET Physics Semiconductor Electronics NOT Gate

NAND Gate

NEET Physics Semiconductor Electronics NAND Gate

NEET Study Material for Semiconductor Electronics Chapter

NOR Gate

NEET Physics Semiconductor Electronics NOR Gate

NOT Gate Using ‘NAND’ Gate

NEET Physics Semiconductor Electronics NOT Gate Using ‘NAND’ Gate

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AND Gate Using NAND Gate

NEET Physics Semiconductor Electronics AND Gate Using NAND Gate

OR Gate From NAND Gate

NEET Physics Semiconductor Electronics OR Gate From NAND Gate

Basic Laws of Boolean Algebra

Boolean Postulates:

0 + A = A

1 . A = A

1 + A = 1

0 . A = 0

\(\mathrm{A}+\overline{\mathrm{A}}=1\)

Identify law:

A + A = A, A. A = a

Negation law:

\(\overline{\mathrm{A}}=\mathrm{A}\)

PN Junction Diode and Transistors NEET Notes

Commutative law:

A + B = B + A

A . B = B. A

Association law:

(A + B) + C = A + (B + C)

(A. B) . C = A . (B . C)

Distribute law:

A . (B + C) = A . B + A . C

NEET Physics Nuclei Notes

NEET Physics Nuclei Notes Nuclei

Nucleons. Protons and neutrons which are present in the nuclei of the atoms are collectively known as nucleons.

Atomic number. The number of protons present in the nucleus is called the atomic number.

It is denoted by Z.

Mass number. The total number of protons and neutrons present in the nucleus is called the mass number of the element. It is denoted by A.

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Number of protons in an atom = Z, Number of electrons in an atom = Z

Number of nucleons in an atom = A, Number of neutrons in an atom = N = A – Z.

Nuclear mass. The total mass of the protons and neutrons present in the nucleus is called the nuclear mass.

Isotopes. Nuclei having the same atomic number but different mass numbers are called isotopes.

Example: Hydrogen has three isotopes

\({ }_1^1 H,{ }_1^2 H \text { and }{ }_1^3 H \text {. }\)

Isobars. Nuclei having different atomic numbers but the same mass number are called isobars.

They contain different numbers of protons hence they are atoms of different elements.

\(\text { Example: (1) }{ }_1^3 \mathrm{H} \text { and }{ }_2^3 \mathrm{He}(2){ }_{18}^{40} \mathrm{Ar} \text { and }{ }_{20}^{40} \mathrm{Ca}\)

NEET Physics Nuclei Notes

Isotones. Nuclei having an equal number of neutrons but different atomic numbers are called isotones. \({ }_1^3 \mathrm{H} \text { and }{ }_2^4 \mathrm{He}\) are isotones since they contain 2 neutrons.

Isomers. The nuclei having the same atomic number and same mass number but differ from one another in their internal structure and their nuclear energy states are called isomers. For example, the stable nucleus of \({ }_{38}^{87} \mathrm{Sr}\) has an isomer which emits gamma rays with a half life of 2.8 hour.

Mirror nuclei. Nuclei having the same mass number but the proton number and neutron number interchanged are called mirror nuclei. For example, \({ }_1^3 \mathrm{H} \text { and }{ }_2^3 \mathrm{He}\) are mirror nuclei.

Atomic mass unit. Atomic mass and nuclear mass are measured in terms of atomic mass unit (u). One atomic mass unit (1u) is defined as \(\frac{1}{12}^{t h}\) the mass of an atom of carbon- 12. Thus,

\(\begin{aligned}
& 1 \mathrm{u}=\frac{\text { mass of one atom of }{ }^{12} \mathrm{C}}{12} \\
& ∴ 1 \mathrm{u}=1.66 \times 10^{-27} \mathrm{~kg} \\
& ∴ \text { Mass of carbon-12 is, } 12 \mathrm{u} .
\end{aligned}\)

NEET Physics Nuclei Notes

NEET Physics Nuclei Important Formulas

\(Mass of proton is, m_p=1.00727 u=1.00727 \times 1.66 \times 10^{-27}\) \(=1.67262 \times 10^{-17} \mathrm{~kg}\) \(Mass of neutron is, \mathrm{m}_n=1.00866 \mathrm{u}=1.6749 \times 10^{-27} \mathrm{~kg}\) \(Mass of electron is, \mathrm{m}_{\boldsymbol{c}}=0.00055 \mathrm{u}=9.13 \times 10^{-31} \mathrm{~kg}\)

Size of the nucleus. From experimental observations, it has been found that the volume of the nucleus is proportional to the number of nucleons present in it (or mass number A). Generally, nuclei are found to have a spherical shape.

\(R=R_0 A^{1 / 3}\)

Where Ro is a constant of proportionality. R = Ro when A = 1. Thus Ro represents the radius of the nucleus of a hydrogen atom which is nothing but a proton. From experiments, it has been found that Ro \(1.3 \times 10^{-15} \mathrm{~m}=1.3 \text { fermi }\)

Nuclear charge. If Z is the number of protons present in the nucleus then a charge of the nucleus is given by,

\(\mathrm{q}=+Z e, \mathrm{e}=1.602 \times 10^{-19} \mathrm{C}\)

Best Short Notes for Nuclei NEET

Nuclear density. \(\text { Nuclear density }=\frac{\text { mass }}{\text { volume }}\)

Consider a nucleus of mass number A and let the mass of each nucleon is \(\mathrm{m}_{\mathrm{N}}=1.67 \times 10^{-27} \mathrm{~kg}\)

\(\text { Nuclear density }=\frac{A m_N}{\frac{4}{3} \partial R^3}=\frac{A m_N}{\frac{4}{3} \partial\left(R_0 A^{1 / 3}\right)^3}=\frac{A m_N}{\frac{4}{3} \partial R_0^3 A}\) \(=\frac{3 m_N}{4 \delta R_0^3}=\frac{3 \times 1.67 \times 10^{27}}{4 \delta \times\left(1.3 \times 10^{-15}\right)^3}=1.815 \times 10^{17} \mathrm{kgm}^{-3}\)

The nuclear density does not depend on mass number A or the number of nucleons in the nucleus. Hence nuclei of all elements have nearly the same density.

Mass energy relation. Before the special theory of relativity, it was presumed that mass and energy were conserved separately in a reaction. However, Einstein showed that mass is another form of energy and one can convert mass energy into other forms of energy.

Einstein’s mass-energy equivalence relation is given by, E=mc²

Here the energy equivalent of mass m is related by the above equation and c is the velocity of light in vacuum and is approximately equal to \(3 \times 10^8 \mathrm{~m} / \mathrm{s}\)

Energy Equivalent of One Atomic Mass Unit

\(∴\mathrm{lu}=931 \mathrm{MeV}\)

Mass defect. The difference between the sum of the masses of the constituent nucleons and the actual mass of the nucleus is called mass defect.

Let M be the mass of the nucleus having mass number A and atomic number Z. If mp is the mass of the proton and mn is the mass of the neutron, the mass defect of the nucleus is,

\(\Delta \mathrm{M}=\left[\mathrm{Zm}_{\mathrm{p}}+(\mathrm{A}-\mathrm{Z}) \mathrm{m}_{\mathrm{n}}\right]-\mathrm{M}\)

Binding energy. The binding energy of a nucleus can be defined as the minimum energy required to split the nucleus into its constituent nucleons.

Note. Mass defect is equivalent to binding energy.

\(\mathrm{E}_{\mathrm{b}}=\left[\mathrm{Z} \mathrm{m}_{\mathrm{p}}+(\mathrm{A}-\mathrm{Z}) \mathrm{m}_{\mathrm{n}}-\mathrm{M}\right] \mathrm{c}^2\)

The ratio of the binding energy of a nucleus to the number of nucleons in that nucleus is called binding energy per nucleon or specific binding energy.

\(\text { i.e., } E_{b a}=\frac{E_b}{A}\)

NEET Physics Nuclei Energy Equivalent of One Atomic Mass Unit

Nuclei NEET Important Questions and Answers

NEET Physics Nuclei Notes

The binding energy per nucleon is close to the maximum value for nuclei in the medium mass number range of 30 to 170. Hence they have great stability. Binding energy per nucleon is maximum for \({ }_{26}^{56} \mathrm{Fe}\)

For higher mass numbers, the specific binding energy is lower and hence they are less stable.

For example, the last few naturally available elements exhibit radioactivity because of lesser stability.

The nature of the binding energy curve gives a clue to the release of energy in a nuclear process.

For example, lighter nuclei having lesser specific binding energy undergo fusion to form a nucleus of higher specific binding energy, resulting in the release of energy. Very heavy nuclei undergo fission to form medium-sized nuclei having greater specific binding energy, resulting in the release of energy.

Packing fraction: The mass defect per nucleon is called the packing fraction.

\(f=\frac{\Delta m}{A}=\frac{M-A}{A}\)

M = mass of the nucleus

A = mass number

NEET Physics Nuclei Packing fraction

NEET Physics Nuclei MCQs with Solutions

The packing fraction measures the stability of nucleons. The smaller the value of the packing fraction, the larger the stability of the nucleons.

Nuclear force. We know that for average mass nuclei, the binding energy per nucleon is approximately 8MeV, which is much larger than the binding energy in atoms. Therefore to bind a nucleus together there must be a strong attractive force of a different kind. It must be strong enough to overcome the repulsion between the protons to bind both protons and neutrons into a tiny nuclear volume.

NEET Physics Nuclei Notes

Characteristics of Nuclear Force

  • Nuclear forces are the strongest known forces in nature.
  • Nuclear forces are short-range forces.
  • Nuclear forces are charge-independent.
  • Nuclear forces have the property of saturation.
  • Nuclear forces are spin-dependent.
  • Nuclear forces are exchange forces.
  • Nuclear forces have a repulsive core.
  • Nuclear forces are non-central.

Radioactivity. The phenomenon of spontaneous disintegration of the nuclei of heavy elements with the emission of certain radiation is called radioactivity.

Law of radioactive decay: The rate of disintegration of a radioactive substance at any instant of time is directly proportional to the number of atoms of that substance present at that instant of time.

\(
N=N_0 e^{-\lambda t}
when \mathrm{t}=\frac{1}{\lambda}, \quad \mathrm{N}=\mathrm{N}_0 e^{-1} \Rightarrow \mathrm{N}=\frac{1}{e} \mathrm{~N}_0=0.3679 N_0\)

Therefore decay constant of a radioactive substance is defined as the reciprocal of the time during which the number of atoms of the substance decreases times the number of atoms originally present.

Half-life. Half life of a radioactive substance is defined as the time during which half of the original atoms disintegrate.

∴\(\mathrm{T}_{12}=\frac{0.693}{\lambda}\)

Mean life. The mean life or average life of a radioactive substance is the ratio of the sum of lives of all the individual atoms to the total number of atoms present in the sample \((\tau)\).

\(\tau=\frac{1}{\lambda}\)

Radioactivity and Nuclear Reactions NEET Notes

Activity. The activity of a radioactive sample is a measure of the number of disintegrations per second or the rate of disintegrations in it.

Since the magnitude of the rate of disintegration is, \(\left|\frac{d N}{d t}\right|=\lambda N\) , i.e., we have activity, A= \(\mathrm{A}=\lambda N\)

The S.I. unit of activity is becquerel (Bq).

Activity is one becquerel if there is one disintegration per second in the substance.

The commonly used unit is curie (Ci).

One curie is the activity of a radioactive sample in which atoms disintegrate per second. It is also the activity of one gram of radium.

∴\(1 \mathrm{Ci}=3.7 \times 10^{10} \text { disintegrations } / \text { second }=3.7 \times 10^{10} \mathrm{~Bq} \text {. }\)

NEET Physics Nuclei Notes

Note:

1. Radioactivity is a nuclear phenomenon. It is not affected by external factors such as temperature, pressure, electric and magnetic fields, chemical reactions, etc. The activity depends only on the radioactive substance and the number of atoms taken.

2. If A0 is the initial activity and A is the activity of a substance at an instant of time t, then

\(\mathrm{A}=\mathrm{A}_0 \mathrm{e}^{\mathrm{it}} \text { and } \mathrm{t}=2.303 \log _{10}\left(\frac{\mathrm{A}_0}{\mathrm{~A}}\right)\)

Alpha decay. Alpha decay is a process in which a nucleus decays spontaneously emitting an alpha particle. These α-particles have discrete values of energy. When a nucleus decays with the emission of α-particle (helium nucleus), the product nucleus (daughter nucleus) has atomic number two less and mass number four less than that of the decaying nucleus (parent nucleus).

In general,

\(\begin{aligned}
& { }_z^A \mathrm{X} \rightarrow{ }_{\mathrm{z}-2}^{\mathrm{A}} \mathrm{Y}+{ }_2^4 \mathrm{He} \\
& \mathrm{Eg}:{ }_{92}^{238} \mathrm{U} \rightarrow{ }_{90}^{234} \mathrm{Th}+{ }_2^4 \mathrm{He}
\end{aligned}\)

This spontaneous decay is possible only when the total mass of decay products is less than the mass of the initial nucleus. The decrease in mass during the decay appears as K.E. of the products.

The disintegration energy or Q-value of the reaction is the difference between the initial mass energy and the total mass energy of the decay products.

\(\text { i.e., } Q=\left(M_X-M_Y-m_\alpha\right) c^2\)

Where MX, MY & mα are the masses of the initial nucleus, product nucleus, and alpha particle. Q>0 for exothermic processes such as α-decay.

Β Decay

β –decay is a process in which a nucleus decays spontaneously emitting an electron or positron. During the β –decay process of a nucleus, the mass number of the product nucleus remains the same but its atomic number changes by one.

A common example of β decay is

\(
{ }_{15}^{32} P \rightarrow{ }_{16}^{32} S+e^{-}+\bar{v}
and that of \beta^* decay is
{ }_{11}^{22} \mathrm{Na} \rightarrow{ }_{10}^{22} \mathrm{Ne}+e^{+}+v
\)

NEET Physics Nuclei Β Decay

NEET Study Material for Nuclei Chapter

Nuclear fission. Nuclear fission is the process in which the nucleus of an atom of a heavy element breaks up into two nuclei of comparable masses with the release of a large amount of energy.

The most important neutron-induced nuclear reaction is fission. An example of fission is when a uranium isotope \({ }_{92}^{235} \mathrm{U}\) bombarded with a neutron breaks into two intermediate-mass nuclear fragments

\({ }_0^1 n+{ }_{92}^{235} U \rightarrow{ }_{92}^{236} U \rightarrow{ }_{56}^{144} \mathrm{Ba}+{ }_{36}^{89} \mathrm{Kr}+3{ }_0^1 n\)

The same reaction can produce other pairs of intermediate mass fragments

\(\begin{gathered}
{ }_0^1 n+{ }_{92}^{235} \mathrm{U} \rightarrow{ }_{92}^{236} \mathrm{U} \rightarrow{ }_{51}^{133} \mathrm{Sb}+{ }_{41}^{99} \mathrm{Nb}+4{ }_0^1 n \text { or, } \\
{ }_0^1 n+{ }_{92}^{235} \mathrm{U} \rightarrow{ }_{92}^{236} \mathrm{U} \rightarrow{ }_{54}^{140} \mathrm{Xe}+{ }_{38}^{94} \mathrm{Sr}+2{ }_0^1 n
\end{gathered}\)

1. Controlled chain reaction. In this type, the chain reaction is first accelerated so that the neutron population is built up to a certain level and thereafter the number of fission-producing neutrons is kept constant. As a result, the energy is released in a controlled manner at a constant rate. This forms the principle of a nuclear reactor.

2. Uncontrolled chain reaction. In this type, the number of neutrons is allowed to multiply indefinitely by increasing the frequency of fissions so that the entire energy is released in a very short interval of time. The energy released will be uncontrolled and it results in a violent explosion. This forms the principle of an atom bomb.

An average of 2.5 neutrons are released in a single fission of . In order to achieve a self-propagating nuclear reaction, at least one of the neutrons in the fission must be captured by another \(\) nucleus and cause further fission. This possibility is determined by a quantity called reproduction constant or multiplication factor denoted by K. It is defined as the ratio of the
secondary neutrons produced to the original neutrons.

\(\text { i.e., } K=\frac{\text { number of neutrons in one event }}{\text { number of neutrons in the preceding event }}\)

Nuclear reactor. A nuclear reactor is a device in which a controlled nuclear chain reaction can be initiated and sustained to harness nuclear energy for constructive purposes.

The essential components of a nuclear reactor are:

Nuclear fuel. The core of the reactor is the site of nuclear fission. It contains the fuel elements in suitably fabricated form. The fuel may be \({ }_{94}^{239} \mathrm{Pu}\) or enriched uranium (i.e., one that has a greater abundance of \({ }_{92}^{235} U\) than naturally occurring uranium).

1. Moderator. The average energy of a neutron produced in fission of \({ }_{92}^{235} U\) is 2MeV. These neutrons unless slowed down will escape from the reactor without interacting with the uranium nuclei, unless a very large amount of fissionable material is used for sustaining the chain reaction. What one needs to do is to slow down the fast neutrons by elastic scattering with light nuclei. Therefore, in reactors, light nuclei called moderators are provided along with the fissionable nuclei for slowing down fast neutrons. The moderators commonly used are water, heavy water (D2O) and graphite.

2. Control rods. The reaction can be shut down by means of control rods (made of, for example, cadmium) that have high absorption of neutrons. The K value can be varied in a reactor by the proper use of these rods, hence are called control rods.

3. Cooling system. The energy (heat) released in fission is continuously removed by a suitable coolant. The coolant transfers heat to a working fluid which in turn may produce steam. The steam drives turbines and generates electricity. The coolants used are carbon dioxide gas or ordinary water when graphite is the moderator. Heavy water is used also as a coolant when it is used as a moderator.

4. Reflector. The core is surrounded by a reflector to reduce leakage. This helps in the reduction of critical size. The commonly used reflector is graphite.

5. Safety system & protective shield. The problems of reactor safety are very vast and complex. All reactors are provided with a backup cooling system as a safety measure. This system takes over if the regular cooling system fails.

A reactor is provided with adequate shielding to minimize the biological effects of harmful radiation ( -rays and neutrons ). The shield is generally a 2m thick concrete wall surrounding the reactor.

Nuclear fusion. Nuclear fusion is the opposite of nuclear fission. It is the process in which two lighter nuclei fuse to form a heavier nucleus with the liberation of energy

\({ }_1^1 \mathrm{H}+{ }_1^1 \mathrm{H} \rightarrow{ }_1^2 \mathrm{H}+\mathrm{e}^{+}+\mathrm{v}+0.42 \mathrm{MeV}\)

Controlled thermonuclear fusion. In controlled fusion reactors, the aim is to generate steady power by heating the nuclear fuel to a temperature in the range of 108 K. At these temperatures, the fuel is a mixture of positive ions and electrons (plasma). The challenge is to combine this plasma, since no container can stand such a high temperature. This can be done by using a magnetic bottle.

NEET Physics Atoms Notes

NEET Physics Atoms Notes

Atoms

Important facts about Rutherford’s α–α-scattering experiment:

  • Most of the α–particles do not suffer collisions with the gold foil.
  • Only about 0.14% of the incident α–particles scatter by more than 10.
  • About 1 in 8000 α–particles deflect by more than 900.

Graph of the number of alpha particles scattered versus scattering angle

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NEET Physics Atoms Graph of number of alpha particles scattered versus scattering angle

NEET Physics Atoms Important Questions

Rutherford argued that, for large angle deflection there must be a massive positively charged body in every atom where the total positive charges of the atom are concentrated.

Hence Rutherford is credited with the discovery of the nucleus.

Impact Parameter

It is the perpendicular distance of the initial velocity vector of the α–particle from the center of the nucleus.

NEET Physics Atoms Impact Parameter

Best tricks to solve Atoms problems for NEET

The impact parameter is given by,

\(\mathrm{b}=\frac{\mathrm{Ze}^2 \cot \left(\frac{\theta}{2}\right)}{4 \pi \mathrm{E}_0\left(\frac{1}{2} m v^2\right)} \Rightarrow \mathrm{b} \propto \cot \left(\frac{\theta}{2}\right)\)

The trajectory of α–particle depends on the impact parameter.

In case of a head-on collision, the impact parameter is minimum and the α–particle rebounds back.

For a large impact parameter, the α–particle goes nearly undefeated.

Distance of closest approach: At the distance of closest approach entire K.E. of the alpha particle gets converted into electrostatic P.E.

i,e., \(\begin{aligned}
\frac{1}{2} \mathrm{mv}^2 & =\left(\frac{1}{4 \pi \varepsilon_0}\right) \frac{(\mathrm{Ze})(2 \mathrm{e})}{\mathrm{r}_0} \\
\mathrm{r}_0 & =\frac{9 \times 10^9 \times 4 \mathrm{Ze}^2}{m v^2}
\end{aligned}\)

Bohr’s Model of Atom NEET Questions and Solutions

Bohr’s Quantum Condition

The angular momentum of an electron in the nth stationary orbit is given by,

\(\mathrm{mvr}=\mathrm{n} \frac{\mathrm{h}}{2 \pi} \quad \mathrm{n}=1,2,3, \ldots \ldots \ldots\)

When an electron makes a transition from a higher energy state to a lower energy state, the difference in energy is emitted in the form of electromagnetic radiation.

\(\mathrm{E}_2-\mathrm{E}_1=\mathrm{hv}\)

The orbital radius of electrons in the ‘nth’ orbit is given by:

\(\begin{aligned}
& \mathrm{r}_{\mathrm{n}}=\frac{\mathrm{n}^2 \mathrm{~h}^2 \varepsilon_0}{\pi \mathrm{mZ} \mathrm{e}^2} \\
& \mathrm{r}_{\mathrm{n}} \propto \frac{\mathrm{n}^2}{\mathrm{Z}}
\end{aligned}\)

For hydrogen atom, \(r_n \propto n^2\)

The radius of nth orbit in a hydrogen atom is,

\(\mathrm{r}_{\mathrm{n}}=0.53 \mathrm{n}^2\) A

NEET Physics Atoms Notes

The orbital velocity of electrons is given by:

\(\begin{aligned}
& v_{\mathrm{n}}=\frac{\mathrm{Ze}^2}{2 \varepsilon_0 \mathrm{nh}} \\
& \mathrm{v}_{\mathrm{n}} \propto \frac{\mathrm{Z}}{\mathrm{n}} \\
& \mathrm{v}_{\mathrm{n}}=\frac{\mathrm{Z}}{\mathrm{n}} \frac{\mathrm{c}}{137}
\end{aligned}\)

Where ‘c’ is the speed of light.

In the case of the hydrogen atom,

\(\mathrm{v}_{\mathrm{n}}=\frac{1}{\mathrm{n}} \frac{\mathrm{c}}{137}\) \(\text { If } \mathrm{n}=1, \mathrm{v}_{\mathrm{n}}=\frac{\mathrm{c}}{137} \simeq 2.2 \times 10^6 \mathrm{~ms}^{-1}\)

NEET Atoms Previous Year Questions with Solutions

Expression for total energy

\(\begin{aligned}
& E_n=-\frac{1}{n^2} \frac{m Z^2 e^4}{8 \varepsilon_0^2 h^2} \\
& E_n \propto \frac{Z^2}{n^2} \\
& E_n=(-13.6) \frac{Z^2}{n^2} e V
\end{aligned}\)

For hydrogen atoms,

\(\mathrm{E}_{\mathrm{n}}=\frac{-13.6}{\mathrm{n}^2} \mathrm{eV}\)

If n = 1, then,

E = –13.6 eV

∴ The ionization energy of the hydrogen atom in the ground state is 13.6 eV & its ionization potential is 13.6 V.

\(\begin{aligned}
& \text { K.E. }=+\frac{1}{\mathrm{n}^2} \frac{\mathrm{mZ^{2 }} \mathrm{e}^4}{8 \varepsilon_0^2 \mathrm{~h}^2} \\
& \text { P.E. }=-\frac{1}{\mathrm{n}^2} \frac{\mathrm{mZ}^2 \mathrm{e}^4}{4 \varepsilon_0^2 \mathrm{~h}^2} \\
& |\mathrm{E}|=\text { K.E.; P.E. }=2 \mathrm{E}
\end{aligned}\) \(\text { wave number, } \quad \frac{1}{\lambda}=R Z^2\left[\frac{1}{\mathrm{n}_1^2}-\frac{1}{\mathrm{n}_2^2}\right]\)

Energy Level Diagram For Hydrogen

NEET Physics Atoms Energy Level Diagram For Hydrogen

No. of spectral lines emitted is given by, \(\frac{\mathrm{n}(\mathrm{n}-1)}{2}\)

NEET Physics Atoms No. of spectral lines emitted

Hydrogen Spectrum and Energy Levels NEET

The time period of revolution of an electron is given by,

\(\begin{aligned}
& T=\frac{2 \pi r}{v} \\
& T \propto \frac{r}{v} \Rightarrow T \propto \frac{n^2}{\frac{1}{n}} \Rightarrow T \propto n^3 \\
& f \propto \frac{1}{T} \Rightarrow f \propto \frac{v}{r} \Rightarrow f \propto \frac{1}{n^3}
\end{aligned}\)

The wavelength of light emitted by hydrogen atoms is,

\(\lambda=\frac{12,420}{\Delta \mathrm{E}(\mathrm{eV})}^{\circ} \mathrm{A}\)

The atom stays in the excited state for about 10 nanoseconds.

Rydberg’s constant is not the same for all elements.

It is the same for elements having the same number of electrons.

The permitted value of ‘n’ ranges up to. However, only values up to 7 have so far been observed.

Balmer series was the first observed spectral series.

The B.E. of the electron in the ground state of hydrogen is called rydberg.

⇒ 1 rydberg = 13.6 eV

NEET Physics Dual Nature Of Radiation And Matter Notes

NEET Physics Dual Nature of Radiation And Matter Notes

Dual Nature of Radiation and Matter

The energy gained by an electron when it is accelerated between a potential difference of 1 volt is called 1eV.

The minimum energy required by an electron to escape from the metal surface is called work function \(\left(\phi_0\right)\)

Caesium (Cs) has the least work function (2.14 eV)

Read And Learn More: NEET Physics Notes

Platinum (Pt) has the highest work function (5.65 eV)

The phenomenon of emission of free electrons from a metal surface on illumination of electromagnetic radiation of suitable frequency is called the Photoelectric Effect.

Maximum kinetic energy of emitted photoelectrons is given by,

\(K_{\max }=e V_0\)

where V0 is stopping potential.

Experimental Observations of Photoelectric Effect

NEET Physics Dual Nature of Radiation and Matter Experimental Observations of Photoelectric Effect

Dual Nature of Radiation and Matter NEET Important Questions

1. Above threshold frequency, the photocurrent is directly proportional to intensity of incident light.

2. Saturation current is proportional to intensity of incident radiation but stopping potential is independent of intensity.

NEET Physics Dual Nature of Radiation and Matter Experimental Observations of Photoelectric Effect 2

Step-by-Step Solutions for Dual Nature NEET Problems

3. There exists a certain minimum frequency below which photoemission is absent is called threshold frequency.

NEET Physics Dual Nature of Radiation and Matter Experimental Observations of Photoelectric Effect 3

Photoelectric Effect Questions for NEET with Solutions

4. The photoelectric effect is an instantaneous process.

Note: Wave theory of light failed to explain experimental observations of the photoelectric effect.

Einstein’s Explanation for Photoelectric Effect

According to Einstein when a photon of energy falls on a metal surface, the maximum kinetic energy of emitted photoelectrons is given by,

\(K_{\max }=h v-\phi_0 \rightarrow(1)\)

Where, is the work function of the metal?

Equation (1) is in the form of y = mx + c

i.e., the graph of \(K_{\max }\)versus will be a straight line with slope h.

\(\begin{aligned}
(1) \Rightarrow e V_0 & =h v-\phi_0 \quad\left(∵ K_{\max }=e V_0\right) \\
V_0 & =\left(\frac{h}{e}\right) v-\frac{\phi_0}{e} \rightarrow(2)
\end{aligned}\)

Equation (2) is also in the form of y = mx + c

i.e., the graph V0 of verses is a straight line with slope \(\frac{h}{e}\)

Dual Nature of Radiation and Matter NEET Notes

De Broglie Wavelength Formula and Questions for NEET

Important properties of photon

  • Momentum of the photon is \(\frac{E}{c}=\frac{h v}{c}\)
  • The rest mass of a photon is zero.
  • Photons are electrically neutral; they are not deflected by electric or magnetic fields.

Matter waves

Waves associated with moving matter are called matter waves.

According to Louis de Broglie wavelength of matter waves is given by,

\(\lambda=\frac{h}{P}=\frac{h}{m v}\)

Consider a particle of mass m and charge q accelerated from rest through a potential V. Then The kinetic energy of the charged particle is given by,

K = qV

\(\text { w.k.t., } \lambda=\frac{h}{P}=\frac{h}{\sqrt{2 m K}}\) \(\Rightarrow \lambda=\frac{h}{\sqrt{2 m q V}}\)

For an electron,

\(\lambda=\frac{h}{\sqrt{2 m e V}}=\frac{1.227}{\sqrt{V}} \mathrm{~nm}\)

NEET Physics Chapter Wise Weightage Dual Nature of Radiation

Note: Davisson and Germer’s experiment proved the wave nature of electrons.

According to Heisenberg’s uncertainty principle, it is impossible to measure two canonically conjugate physical quantities like the position and momentum of a microscopic entity simultaneously and accurately.

Or in simple form,

It is impossible to measure the position and momentum of a microscopic particle accurately and simultaneously.

NEET Physics Electromagnetic Waves Notes

Electromagnetic Waves

Ampere’s Circuital Law

Maxwell modified the Ampere’s circuital law \(\oint \overrightarrow{\mathrm{B}} \cdot \mathrm{d} \vec{\ell}=\mu_0 \mathrm{I}\) to explain the continuity of current in a circuit containing a capacitor.

⇒ \(\phi=\mathrm{EA}=\frac{\sigma}{\mathrm{s}_0} \mathrm{~A}=\frac{\mathrm{Q}}{\mathrm{A} \varepsilon_0} \mathrm{~A}\)

⇒ \(\frac{\mathrm{d} \phi}{\mathrm{dt}}=\frac{1}{\varepsilon_0} \frac{\mathrm{dQ}}{\mathrm{dt}}\)

⇒ \(\mathrm{I}_{\mathrm{d}}=\frac{\mathrm{dQ}}{\mathrm{dt}}=\varepsilon_0 \frac{\mathrm{dQ}}{\mathrm{dt}}\)

NCERT Summary of Electromagnetic Waves for NEET

This was the missing term suggested by Maxwell, which is called displacement current ID.

Read And Learn More: NEET Physics Notes

Displacement current is due to the rate of change of electric field between the plates of the capacitor

Conduction current and the displacement in a circuit may not be continuous but their sum is always continuous.

A modified form of Ampere’s circuital law / Ampere–Maxwell law is,

⇒ \(\oint \overrightarrow{\mathrm{B}} \cdot \mathrm{d} \vec{\ell}-\mu_0 \mathrm{I}+\varepsilon \mu_0 \frac{\mathrm{d} \phi_1}{\mathrm{dt}}\)

Electromagnetic Wave Propagation Visualization

Electromagnetic Waves NEET Important Questions

Maxwell’s Equations

\(1. \oint \vec{E} \cdot d \vec{A}=\frac{Q}{e_0} (Gauss’ law of electricity)\)

 

\(2. \oint \overrightarrow{\mathrm{B}} \cdot \mathrm{d} \overrightarrow{\mathrm{A}}=0 (Gauss’ law for magnetism)\)

 

\(3. \oint \overrightarrow{\mathrm{E}} \cdot \mathrm{d} \vec{\ell}=-\frac{\mathrm{d} \phi_{\mathrm{B}}}{\mathrm{dt}} (Faraday’s law)\)

 

\(4. \oint \overrightarrow{\mathrm{B}} \cdot \mathrm{d} \vec{\ell}-\mu_0 \mathrm{i}_{\mathrm{c}}+\mu_0 \varepsilon_0 \frac{\mathrm{d} \phi}{\mathrm{dt}} (Ampere – Maxwell law)\)

 

Representation of An Electromagnetic Wave:

NEET Physics Electromagnetic Waves Representation of An Electromagnetic Wave

\(\begin{aligned}
& E_{\mathrm{z}}=\mathrm{E}_0 \sin (\mathrm{kz}-\omega \mathrm{t}) \\
& \mathrm{B}_{\mathrm{y}}=\mathrm{B}_0 \sin (\mathrm{kz}-\omega \mathrm{t})
\end{aligned}\)

Difference Between Mechanical and Electromagnetic Waves NEET

The direction of the EM wave is given by \(\overrightarrow{\mathrm{E}} \times \overrightarrow{\mathrm{B}}\)

\(\begin{aligned}
\frac{\mathrm{E}_0}{\mathrm{~B}_0} & =\mathrm{c} \\
\mathrm{k} & =\frac{2 \pi}{\lambda}, \omega=2 \pi \mathrm{f} \\
\frac{\omega}{\mathrm{k}} & =\frac{2 \pi \mathrm{f}}{2 \pi} \lambda=\mathrm{c} \\
\mathrm{c} & =\frac{1}{\sqrt{\mu_0 \varepsilon_0}}
\end{aligned}\)

Best Notes for Electromagnetic Waves NEET Preparation

The velocity of light in a medium is given by,

\(\begin{aligned}
& \mathrm{v}=\frac{1}{\sqrt{\mu \varepsilon}}=\frac{1}{\sqrt{\mu_0 \mu_{\mathrm{r}} \varepsilon_0 \varepsilon_{\mathrm{r}}}} \\
& \mathrm{v}=\frac{1}{\sqrt{\mu_0 \varepsilon_0}} \times \frac{1}{\sqrt{\mu_{\mathrm{r}} \varepsilon_{\mathrm{t}}}} \\
& \mathrm{v}=\frac{\mathrm{c}}{\sqrt{\mu_z \varepsilon_{\mathrm{r}}}}
\end{aligned}\)

The rate of energy transported per unit area by EM wave is given by,

Pointing vector, \(\overrightarrow{\mathrm{S}}=\frac{\mathrm{EB}}{\mu_0}=\frac{\mathrm{E}^2}{\mu_0 \mathrm{c}}\)

The energy density of the electric field is given by,

\(u_E=\frac{1}{2} \varepsilon_0 E^2\)

Properties and Applications of Electromagnetic Waves NEET MCQs

The energy density of the magnetic field is given by,

\(\mathrm{u}_{\mathrm{B}}=\frac{\mathrm{B}^2}{2 \mu_0}\)
  • Average electric energy density = average magnetic energy density.
  • The intensity of the EM wave is given by,
\(\mathrm{I}=\mathrm{U}_{\mathrm{m}} \mathrm{c}=\frac{\mathrm{B}_0^2}{2 \mu_0} \mathrm{c}=\frac{1}{2} \varepsilon_0 \mathrm{E}_0^2 \mathrm{c}\)
  • The electric vector is responsible for all optical effects. This vector is also known as the light vector.
  • The pressure exerted by an EM wave is given by,
\(\mathrm{P}=\frac{\mathrm{I}}{\mathrm{c}}\)
  • The momentum carried by an EM wave is given by,
\(\mathrm{P}=\frac{\mathrm{U}}{\mathrm{c}}\)

NEET Physics Electrostatic Potential And Capacitance Notes

NEET Physics Electrostatic Potential and Capacitance Notes

Electrostatic Potential And Capacitance

Electrostatic Potential Definition:

The electric potential at a point is defined as the work done in bringing a unit positive charge (with uniform speed) from infinity to that point against the electrostatic force of the field.

V = \(\frac{W}{q}\)

Charges always flow from a body at a higher potential to a body at a lower potential.

Electric potential due to a point charge is given by,

\(\mathrm{V}=\frac{1}{4 \pi \varepsilon_0} \frac{\mathrm{q}}{\mathrm{r}}\)

Read And Learn More: NEET Physics Notes

Electric potential is a scalar quantity.

\(1 \text { volt }=\frac{1 \text { joule }}{1 \text { coulomb }} \Rightarrow 1 \mathrm{~V}=\frac{1 \mathrm{~J}}{1 \mathrm{C}}\)

The electric potential at any general point due to a dipole is given by

\(\mathrm{V}=\frac{1}{4 \pi \varepsilon_0} \frac{\mathrm{p} \cos \theta}{\mathrm{r}^2}\)

Best Notes for Electrostatic Potential and Capacitance NEET

Where ‘p’ is electric dipole moment θ, is the angle between \(\overrightarrow{\mathrm{r}} \text { and } \overrightarrow{\mathrm{p}}\).

A surface with the same value of potential at all points on the surface is known as an equipotential surface.

The p.d. between any two points on the equipotential surface is zero.

The work done in transferring a charge from one point to another on an equipotential surface is zero.

Electric Field and Potential Are Related as

E = \(\frac{dV}{dr}\)

Where \(\frac{dV}{dr}\) is known as a potential gradient.

The potential energy of a system of two charges is given by,

\(\mathrm{U}=\frac{1}{4 \pi \varepsilon_0} \frac{\mathrm{q}_1 \mathrm{q}_2}{\mathrm{r}_{12}}\)

Where r12 is the distance between two charges.

The potential energy of a system of three charges is given by,

NEET Previous Year Questions on Electrostatic Potential and Capacitance

\(\mathrm{U}=\frac{1}{4 \pi \varepsilon_0}\left[\frac{\mathrm{q}_1 \mathrm{q}_2}{\mathrm{r}_{12}}+\frac{\mathrm{q}_1 \mathrm{q}_3}{\mathrm{r}_{13}}+\frac{\mathrm{q}_2 \mathrm{q}_3}{\mathrm{r}_{23}}\right]\)

In general, for ‘n’ charges.

\(\mathrm{U}=\frac{1}{4 \pi \varepsilon_0} \sum_{\text {alpuis }} \frac{\mathrm{q}_{\mathrm{i}} \mathrm{q}_{\mathrm{j}}}{\mathrm{r}_{\mathrm{ij}}}\)

The atoms or molecules in which the effective positive charge center and negative charge center do not coincide are called polar molecules.

A dielectric made of polar molecules is called a polar dielectric. The atoms or molecules in which the effective positive charge center and negative charge center coincide are called non–polar molecules.

A dielectric made of non–polar molecules is called non–polar dielectric.

The dipole moment per unit volume of the dielectric is called polarisation.

Polarisation, \(P=\chi_e E\)

Where Xe is known as the electrical susceptibility of the dielectric medium.

When a very high electric field is applied to the insulator, the force experienced by the valence electrons may be large enough to get pulled from the atom. Now electrons constitute current inside the insulator. This is known as the breakdown of dielectric or the breakdown of an insulating material.

The minimum value of an electric field that produces a breakdown of the dielectric is known as the dielectric strength of the dielectric.

NCERT Summary of Electrostatic Potential and Capacitance for NEET

Reason for Lightening

When the electric field developed by the charged cloud becomes greater than the dielectric strength of air, then there will be a huge electric discharge. This is the reason for lightening.

The dielectric strength of dry air is about 3×106V/m.

The capacitor is a device that stores energy in the form of an electric field.

Or

It is a system of two conductors separated by a distance used to store electric charge.

The capacitance of a capacitor ‘C’ is given by

\(\frac{Q}{V}\)

Where ‘Q’ is the charge stored and ‘V’ is the potential difference.

Note:

A single conductor also has the capacity to store charges.

The capacitance of a spherical conductor is given by,

\(\mathrm{C}=\frac{\mathrm{Q}}{\mathrm{V}}=\frac{\mathrm{Q}}{\frac{1}{4 \pi \varepsilon_0} \frac{\mathrm{Q}}{\mathrm{R}}}\) \(\mathrm{C}=4 \pi \mathrm{x}_0 \mathrm{R}\)

Where ‘R’ is the radius of the conductor.

The capacitance of a parallel plate air capacitor is given by,

\(C=\frac{\varepsilon_p A}{d}\)

Where ‘A’ is the area of capacitor plates and ‘d’ is the distance between capacitor plates.

Step-by-Step Solutions for Electrostatic Potential NEET Problems

When a parallel plate capacitor is filled with a dielectric of dielectric constant ‘K’ then,

\(C=K\left(\frac{\varepsilon_0 A}{d}\right)\)

i.e., the capacitance increases K times.

The capacitance of a capacitor when it is partially filled with dielectric

\(C=\frac{\varepsilon_0 A}{(d-t)+\frac{t}{K}}\)

Where ‘t’ is the thickness of the dielectric slab.

The capacitance of a parallel plate capacitor with a conducting slab.

\(\mathrm{C}=\frac{\varepsilon_0 \mathrm{~A}}{\mathrm{~d}-\mathrm{t}}\)

(∵ for a conducting slab K= ∞)

Series Combination of Capacitors

When capacitors are connected in series charge stored in all the capacitors is the same.

The effective capacitance is,

\(\frac{1}{C_5}=\frac{1}{C_1}+\frac{1}{C_2}+\ldots . .+\frac{1}{C_E}\)

When two capacitors of capacitance C1 and C2 are connected in series, then,

\(\frac{1}{C_s}=\frac{1}{C_1}+\frac{1}{C_2}=\frac{C_1+C_2}{C_1 C_2}\) \(\mathrm{C}_{\mathrm{S}}=\frac{\mathrm{C}_1 \mathrm{C}_2}{\mathrm{C}_1+\mathrm{C}_2}\)

When ‘n’ capacitors of equal capacitance ‘C’ are connected in series, then

\(\mathrm{C}_{\mathrm{S}}=\frac{\mathrm{C}}{\mathrm{n}}\)

NEET Physics Electrostatic Potential and Capacitance Notes

Parallel Combination of Capacitors

When ‘n’ capacitors are connected in parallel, the p.d. between each capacitor will be the same.

The effective capacitance is,

Cp= C1 + C2 + …. + Cn

When ‘n’ capacitors of equal capacitance ‘C’ are connected in parallel, then

\(\mathrm{C}_{\mathrm{p}}=\mathrm{nC}\)

The p.d. between two spherical shells of a spherical capacitor is given by,

\(V=\frac{Q}{4 \pi \varepsilon_0}\left[\frac{1}{a}-\frac{1}{b}\right]\)

Where Q is the magnitude of charge on either shell, a is the radius of the inner shell and b is the radius of the outer shell.

Concept of Equipotential Surfaces and Potential Energy for NEET

∴ The capacitance of the spherical capacitor is,

\(\begin{aligned}
& C=\frac{Q}{V} \\
& C=\frac{4 \pi \varepsilon_0 a b}{b-a}
\end{aligned}\)

Energy Stored On A Capacitor Is Given By:

\(\mathrm{U}=\frac{\mathrm{Q}^2}{2 \mathrm{C}}=\frac{1}{2} \mathrm{CV}^2=\frac{1}{2} \mathrm{QV}\)

Note:

When a battery supplies charge to a capacitor, only 50% of the work done by the battery gets stored as energy. The remaining 50% is dissipated in the form of heat.

The Energy Density in a Parallel Plate Capacitor

\(\)

u = \(\frac{U}{V}\)

\(\mathrm{u}=\frac{\frac{1}{2} \mathrm{CV}^2}{\mathrm{Ad}}=\frac{1}{2} \frac{\varepsilon_{\mathrm{g}} \mathrm{A} \mathrm{V}^2}{\mathrm{~d}(\mathrm{Ad})}\)

\(\mathrm{u}=\frac{1}{2} \varepsilon_0 \mathrm{E}^2\) (∴ E = \(\frac{V}{d}\)

Parallel Plate Capacitor and Energy Stored NEET Questions

Common potential when two capacitors are connected in parallel

\(\mathrm{V}_{\text {coev }}=\frac{\mathrm{C}_1 \mathrm{~V}_1+\mathrm{C}_2 \mathrm{~V}_2}{\mathrm{C}_1+\mathrm{C}_2}\)

The energy loss is given by,

\(\mathrm{U}_{\mathrm{leas}}=\frac{1}{2}\left(\frac{\mathrm{C}_1 \mathrm{C}_2}{\mathrm{C}_1+\mathrm{C}_2}\right)\left(\mathrm{V}_1-\mathrm{V}_2\right)^2\)

NEET Physics Ray Optics and Optical Instruments Notes

NEET Physics Ray Optics and Optical Instruments Notes

Ray Optics And Optical Instruments

Laws of Reflection of Light:

NEET Physics Ray Optics and Optical Instruments Laws of reflection of light

  1. The incident ray, reflected ray, and the normal drawn at the point of incidence all lie in the same plane.
  2. The angle of incidence is equal to the angle of reflection.
\(\text { i.e., }\lfloor i=\lfloor r\)

NEET Physics Ray Optics Important Formulas

Sign conventions:

  • All distances are measured from the pole of the mirror.
  • Distances measured in the direction of incident light are taken positively and vice versa.
  • Heights measured upward and perpendicular to the principal axis are taken positively and vice versa.

Read And Learn More: NEET Physics Notes

For a spherical mirror, the relation between focal length and radius of curvature is,

\(\mathrm{f}=\frac{\mathrm{R}}{2}\)

Where f is the focal length and ‘R’ is the radius of curvature of the mirror.

Mirror equation

\(\frac{1}{f}=\frac{1}{u}+\frac{1}{v}\)

Where u is the object distance and v is the image distance.

Linear magnification is the ratio of the height of the image to the height of the object.

\(\mathrm{m}=\frac{\mathrm{h}_{\mathrm{i}}}{\mathrm{h}_{\mathrm{o}}}\)

For a spherical mirror, \(\mathrm{m}=-\frac{\mathrm{v}}{\mathrm{u}}\)

Best Short Notes for Ray Optics and Optical Instruments NEET

The refractive index of a medium is defined as the ratio of the speed of light in vacuum (c) to the speed of light of medium (v)

\(\mathrm{n}=\frac{\mathrm{e}}{\mathrm{v}}\)

Refractive index of a medium depends on the wavelength of light used.

Longer the wavelength smaller is the refractive index.

Ray Optics NEET Physics Notes

NEET Physics Ray Optics and Optical Instruments Notes

Laws Of Refraction Of Llight

  1. The incident ray, refracted ray and the normal drawn at the point of incidence all lie in the same plane.
  2. Sine of angle of incidence to the sine of angle of refraction is a constant for a given pair of media and for given wavelength of light.
\(\text { i.e., } \frac{\sin i}{\sin r}=\text { constant }=n_{21}\)

Where is the refractive index of medium 2 w.r.to medium 1.

If \(n_{21}>1, \mathrm{r}<\mathrm{i} \text { and if } n_{21}<1, \mathrm{r}>\mathrm{i}\)

Expression for normal shift

N. S .= \(t\left(1-\frac{1}{n}\right)\)

where t is the thickness and n is the refractive index of the medium.

Relation between refractive index and critical angle

\(\sin \mathrm{C}=\mathrm{n}_{21}=\frac{\mathrm{n}_2}{\mathrm{n}_1}\)

Where ‘C’ is the critical angle

Relation between n, u, v, and R for a spherical refracting surface.

\(\frac{\mathrm{n}_2}{\mathrm{v}}-\frac{\mathrm{n}_1}{\mathrm{u}}=\frac{\mathrm{n}_2-\mathrm{n}_1}{\mathrm{R}}\)

Where, n2 is the refractive index of the image medium.

n1 is the refractive index of the object medium.

And R is the radius of curvature.

Lens maker’s formula

\(\frac{1}{\mathrm{f}}=\left(\mathrm{n}_{21}-1\right)\left(\frac{1}{\mathrm{R}_1}-\frac{1}{\mathrm{R}_2}\right)\)

Thin lens formula

\(\frac{1}{v}-\frac{1}{u}=\frac{1}{f}\)

Magnification produced by a lens

\(\mathrm{m}=\frac{\mathrm{v}}{\mathrm{u}}\)

Ray Optics and Optical Instruments NEET Important Questions and Answers

Power of a lens

\(P=\frac{1}{f}\)

The S.I. unit of power of a lens is dioptre (D)

1D = 1m¯¹

Combination of thin lenses in contact

NEET Physics Ray Optics and Optical Instruments Combination of thin lenses in contact

In terms of power,

Peff = P1 + P2 + P3 + ….

In terms of magnification,

Meff = m1. m2 . m3…..

Refraction through a prism

NEET Physics Ray Optics and Optical Instruments Refraction through a prism

At the angle of minimum deviation

\(\begin{aligned}
& \delta=\mathrm{D}_{\mathrm{m}}, \mathrm{i}=\mathrm{e} \Rightarrow r_{\mathrm{i}}=r_2 \\
& \Rightarrow \mathrm{r}=\frac{\mathrm{A}}{2} \\
& \mathrm{D}=\frac{\left(\mathrm{A}+\mathrm{D}_{\mathrm{m}}\right)}{2} \\
& \mathrm{n}_{21}=\frac{\mathrm{n}_2}{\mathrm{n}_1}=\frac{\sin \left(\frac{\left(\mathrm{A}+\mathrm{D}_{\mathrm{m}}\right)}{2}\right)}{\sin \left(\frac{\mathrm{A}}{2}\right)}
\end{aligned}\)

For a small-angle prism,

\(\begin{aligned}
& \mathrm{n}_{21}=\frac{\frac{\left(\mathrm{A}+\mathrm{D}_{\mathrm{m}}\right)}{2}}{\left(\frac{\mathrm{A}}{2}\right)} \\
& \& \mathrm{D}_{\mathrm{m}}=\left(n_{21}-1\right) \mathrm{A}
\end{aligned}\)

NEET Physics Ray Optics and Optical Instruments MCQs with Solutions

Ray Optics

In the above set of equations, i is the angle of incidence, e is the angle of emergence, A isthe  angle of prism & are angle of refractions at two boundaries, is deviation and Dm is the angle of minimum deviation.

According to Rayleigh’s law of scattering if the particle size is greater the then,

Scattering is proportional to \(\frac{1}{\lambda^4}\).

The standard value of the near point of the human eye is D = 25 cm.

Magnification is produced by a simple microscope when the image is produced at a near point,

NEET Physics Ray Optics and Optical Instruments Magnification produced by simple microscope

When the image is formed at infinity,

\(m=\frac{D}{f}\)

Magnification produced by a compound microscope when image is formed at infinity is,

\(\begin{aligned}
& m=m_0 m_e \\
& m=\left(\frac{L}{f_0}\right)\left(\frac{D}{f_e}\right)
\end{aligned}\)

Magnification produced by a compound microscope when image is formed at near point is,

NEET Physics Ray Optics and Optical Instruments Magnification produced by a compound microscope

Reflection and Refraction of Light NEET Notes

Ray Optics

Where, and are the magnification of the objective and eyepiece respectively fo and fe are the focal lengths of the objective and the eyepiece respectively.

Magnification of the telescope is given by,

\(m=\frac{f_o}{f_o}\)

NEET Study Material for Ray Optics and Optical Instruments Chapter

where fo and fe are the focal lengths of the objective and eyepiece respectively.

The magnifying power of a telescope is the ratio of the angle subtended at the eye by the image to the angle subtended at the eye by the object

\(\text { i.e., } \mathrm{m}=\frac{\beta}{\alpha}\)

NEET Physics Alternating Current Notes

NEET Physics Alternating Current Notes

Alternating Current

Let the alternating emf is given by,

\(\varepsilon=\varepsilon_0 \sin \omega t\)

where, \(\varepsilon_0=\mathrm{NAB} \omega\)

The instantaneous value of current is given by

\(\mathrm{I}=\mathrm{I}_0 \sin \omega \mathrm{t}\)

Note:

\(I_m=\frac{I_0}{\sqrt{2}} ; v_{\max }=\frac{v_0}{\sqrt{2}}\)

or

\(\mathrm{I}_{\max }=0.707 \mathrm{I}_0 ; \mathrm{V}_{\max }=0.707 \mathrm{~V}_0\)

Where, Irms & Vrms are effective values & I0 & V0 are the peak values.

NEET Alternating Current Previous Year Questions with Solutions

\(\mathrm{I}_w=\frac{2}{\pi} \mathrm{I}_0=0.637 \mathrm{I}_0=(63.7 \%) \mathrm{I}_0\) \(\mathrm{v}_m=\frac{2}{\pi} \mathrm{V}_0=0.637 \mathrm{~V}_6=(63.7 \%) \mathrm{V}_0\)

Peak to peak value of AC is given by

2V0 or 2I0

Read And Learn More: NEET Physics Notes

Time Difference

If the phase difference between alternating current and voltage is then the time difference between them is,

\(\mathrm{TD}=\frac{\mathrm{T}}{2 \pi} \times \phi\)

The mean value of ac for the half cycle is,

\(I_{\text {mean }}=\frac{2}{\pi} I_0\)

The rms value of current is given by,

\(\mathrm{I}_{\max }=\frac{\mathrm{I}_0}{\sqrt{2}}\)

NEET Physics Alternating Current Notes

NEET Physics Alternating Current Important Questions

Alternating Voltage Applied to a Pure Resistor

\(\begin{aligned}
& \mathrm{V}=\mathrm{V}_0 \sin \omega \mathrm{t} \\
& \mathrm{I}=\mathrm{I}_0 \sin \omega t,
\end{aligned}\)

Where, \(I_0=\frac{V_0}{R}\)

V and I are in phase

Alternating Voltage Applied to a Pure Inductor

\(\begin{aligned}
& V=V_0 \sin \omega t \\
& I=I_0 \sin \left(\omega t-\frac{\pi}{2}\right)
\end{aligned}\)

Where, \(I_0=\frac{V_0}{\omega L}\)

The quantity is analogous to resistance, called inductive reactance.

Inductive reactance, \(\mathrm{X}_{\mathrm{L}}=\omega \mathrm{L}=2 \pi \mathrm{fL}\)

For dc, \(f=0, \Rightarrow X_L=0\)

i.e., the inductor behaves like a wire for dc.

The phase difference between V and I is —.

V leads I by \(\frac{\pi}{2}\)

Alternating Current NCERT Summary for NEET

Alternating Voltage Applied to a Pure Capacitor

\(\mathrm{V}=\mathrm{V}_0 \sin \omega \mathrm{t}
I=I_0 \sin \left(\omega t+\frac{\pi}{2}\right)
\)

Where, \(I_0=\frac{V_0}{\left(\frac{1}{\omega C}\right)}\)

The quantity \(\) is analogous to resistance called capacitive reactance.

Capacitive reactance, \(\left(\frac{1}{\omega \mathrm{C}}\right)\)

For dc, f = 0, Xc = ∞

The phase difference between V and I is \(\frac{\pi}{2}\).

V lags I by \(\frac{\pi}{2}\).

Alternating Voltage Applied to a Series LCR Circuit

The applied alternating voltage is,

\(\mathrm{V}=\mathrm{V}_0 \sin \omega \mathrm{t}\)

The current flowing in the circuit is,

AC Circuit Formulas and Shortcuts for NEET Physics

Ac Current Formula

\(\mathrm{I}=\mathrm{I}_0 \sin (\omega \mathrm{t}+\phi)\) \(\text { Where, } I_4=\frac{V_0}{\sqrt{R^2+\left(\frac{1}{\omega C}-\omega L\right)^2}}\) \(\text { And } \phi=\tan ^{-1}\left(\frac{X_C-X_L}{R}\right)\)

Expression for Average Power in AC Circuits

\(\overline{\mathrm{P}}=\mathrm{V}_{\mathrm{max}} \mathrm{I}_{\mathrm{max}} \cos \phi\)

The term \(\cos \phi\) is called power factor.

For pure resistive circuit, \(\phi=0 \text { i.e., } \cos \phi=1\)

For pure capacitive circuit, \(\phi=\frac{\pi}{2} \text { i.e., } \cos \phi=0\)

For pure inductive circuit, \(\phi=\frac{\pi}{2} \text { i.e., } \cos \phi=0\)

Current in a circuit when no power is dissipated is known as Watt less current.

Electrical Resonance

The current in a LCR circuit is given by

\(
I_0=\frac{V_0}{\sqrt{R^2+\left(X_C-X_L\right)^2}}=\frac{V_0}{Z}
Or, I_0=\frac{V_0}{\left.\sqrt{R^2+\left(\frac{1}{\omega C}-\omega L\right.}\right)^2}\)

Which indicates that at a particular angular frequency \(\omega_0, I_0\) will be maximum, Z or impendence of the circuit is minimum. The corresponding frequency is called resonant frequency.

At resonance, Xc = XL

\(\begin{aligned}
\omega_0 \mathrm{~L} & =\frac{1}{\omega_0 \mathrm{C}} \\
\omega_0^2 & =\frac{1}{\mathrm{LC}} \Rightarrow \omega_0=\frac{1}{\sqrt{\mathrm{LC}}} \\
∴ \mathrm{f}_0 & =\frac{1}{2 \pi \sqrt{\mathrm{LC}}}
\end{aligned}\)
  • For a given value of L and C the resonant frequency does not depend on R.
  • But the maximum current decreases with increase in the value of R.
  • For smaller values of R the resonance curve is more sharp.
  • The sharpness of the resonance curve is indicated by a term called quality factor Q.
  • Quality factor is the ratio of the resonant frequency to the bandwidth.
  • Bandwidth is the difference between half power frequencies.

Ac Circuits Formulas

\(\text { Quality factor }=\frac{\text { resonant frequency }}{\text { bandwidth }}\) \(i.e., Q=\frac{\omega_0}{2 \Delta \omega}
If \omega_0=2 \pi v_0, \omega_1=2 \pi v_1 and $\omega_2=2 \pi v_2\) \(Q=\frac{v_0}{v_2-v_1}\)

Quality factor is also given by,

Alternating Current and AC Circuits NEET

\(Q=\frac{\omega_0}{2 \Delta \omega}=\frac{\omega_0 L}{R}\)

Since, \(\omega_0 L=\frac{1}{\omega_0 C}\) we can also write,

\(Q=\frac{1}{\omega_0 C R}=\frac{1}{R} \sqrt{\frac{L}{C}}\)

If Q value is less, sharpness is less. When sharpness is less, not only the maximum current is less, but also bandwidth is more and the tuning of the circuit will not be good.

If R is low or L is large, the Q is large and the circuit is more selective.

NEET Physics Electromagnetic Induction Notes

NEET Physics Electromagnetic Induction Notes

Electromagnetic Induction

The phenomenon of the production of EMF across an electrical conductor in a changing magnetic field is called electromagnetic induction.

The magnetic flux through a surface is defined as,

\(\phi=\oint \overrightarrow{\mathrm{B}} \cdot \overrightarrow{\mathrm{A}}=\mathrm{BA} \cos \theta\) Where is the angle between a magnetic field and area vector.

Read And Learn More: NEET Physics Notes

Faraday’s Law of EMI

The magnitude of induced emf in a coil is equal to the rate of change of magnetic flux.

\(\text { i.e., } e=-\frac{d \phi}{d t}\)

If there are N turns in the coil,

Electromagnetic Induction NEET Important Questions

\(e=-\frac{N d \phi}{d t}\)

The negative symbol indicates that the induced emf opposes the change in flux.

Lenz’s Law

The direction of induced emf or current in the circuit is such that, it opposes the cause that produced it.

Lenz’s law is in accordance with the law of conservation of energy.

Motional EMF

  1. If a conducting rod of length is moving with a uniform velocity \(\overrightarrow{\mathrm{v}}\) perpendicular to a uniform magnetic field \overrightarrow{\mathrm{B}}, then the magnitude of induced emf in the rod is given by,
    \(\mathrm{e}-\mathrm{B} / \mathrm{v}\)
  2. If a rod is moving by making an angle with the direction of a magnetic field, the
    \(\mathrm{e}=\mathrm{B} / \mathrm{v} \sin \theta\)
  3. If a conductor starts sliding from the top of an inclined plane with the angle of inclination (θ) then,
    \(\begin{aligned}
    & \mathrm{e}=\mathrm{B} l v \sin (90-\theta) \\
    & \Rightarrow \mathrm{e}=\mathrm{B} l v \cos \theta
    \end{aligned}\)

Note:

Consider a conducting rod of length ‘l’ whose one end is fixed, is rotated about the axis passing through its fixed end and perpendicular to its length with constant angular velocity. The magnetic field ‘B’ is perpendicular to plane of the paper, then

NEET Physics Electromagnetic Induction Motional EMF

The induced emf across the ends of the rod is given by,

Faraday’s Law and Lenz’s Law NEET Questions with Solutions

\(\begin{aligned}
&E_{\text {sut }}=\frac{1}{2} \mathrm{~B} / v=\frac{\mathrm{B} l}{2}(\omega /)\\
&\mathrm{E}_{\mathrm{sa}}=\frac{1}{2} \mathrm{~B} \omega \ell^2
\end{aligned}\)

Where \(‘ \omega^{\prime}=2 \pi f\)

Electromagnetic Induction Neet Notes

Self Induction

The phenomenon in which emf is induced in one coil due to a change in current in the same coil is called self-induction.

w.k.t., \(\phi \propto I \text { or } \phi=LI\)

Where L is called the coefficient of self-induction or self-inductance of the coil.

The induced emf in the coil is given by

\(\mathrm{e}=-\frac{\mathrm{d} \phi}{\mathrm{dt}} \Rightarrow \mathrm{e}=-\mathrm{L} \frac{\mathrm{dI}}{\mathrm{dt}}\) \(\text { If } \frac{\mathrm{dI}}{\mathrm{dt}}=1 \mathrm{As}^{-1} \text {, then }|\mathrm{e}|=\mathrm{L}\)

S.I. unit of L is Henry (H).

Dimensional formula of [L] = [ML2 T-2A-2]

Self-inductance of a long solenoid

Where N is the total number of turns, A is the area of the Cross section, and ‘l’ is the length of the solenoid.

Mutual Induction

The phenomenon in which emf is induced in one coil due to a change in current in the neighboring coil is called mutual induction.

Induced emf due to mutual induction is given by,

\(\mathrm{E}=-\mathrm{M} \frac{\mathrm{dI}}{\mathrm{dt}}\)

Mutual Inductance of Two Long Co-Axial Solenoids

\(\mathrm{M}=\frac{\mu_0 \mathrm{~N}_1 \mathrm{~N}_2 \pi \pi_1^2}{l}\)

Where, l is the length of the solenoids, N1 & N2 are the number of turns in the inner and outer solenoids respectively is the radius of the inner solenoid.

Relation Between M, L1 and L2

For two magnetically coupled coils

\(\mathrm{M}=\mathrm{k} \sqrt{\mathrm{L}_1 \mathrm{~L}_2}\)

Where k is the coefficient of coupling or coupling factor.

\(\begin{gathered}
\mathbf{k}=\frac{\text { Magnetic flux linked in secondary }}{\text { Magentic flux linked in primary }} \\
0 \leq \mathrm{k} \leq 1
\end{gathered}\)

NEET Physics Electromagnetic Induction Relation Between M, L1 and L2

NCERT Summary of Electromagnetic Induction for NEET

Combination of Inductors

If two coils of self inductances L1 and L2are in series and are far from each other, so that the mutual induction between them is negligible, then,

Ls = L1 + L2

If L1 and L2 are connected in parallel and if they are far from each other, then,

\(\frac{1}{L_p}=\frac{1}{L_1}+\frac{1}{L_2} \text { or } L_p=\frac{L_1 L_2}{L_1+L_2}\)

Induced emf in a coil is given by,

\(\begin{aligned}
& \mathrm{e}=\mathrm{NBA} \omega \sin \omega \mathrm{t} \\
& \mathrm{e}=\mathrm{e}_0 \sin \omega \mathrm{t}
\end{aligned}\)

Where, \(\mathrm{e}_0=\mathrm{NBA} \omega\) is the peak/maximum value of emf.

Choke coil

It is a device having high inductance and negligible resistance.

NEET Physics Electromagnetic Induction Choke coil

Chapter-wise Weightage for NEET Physics Electromagnetic Induction

It consists of thick copper (Cu) wire to reduce the resistance of the circuit and a soft iron core to improve the inductance of the circuit.

Transformer works on the principle of mutual induction.

The efficiency of a transformer is given by

\(\eta=\frac{\text { Output power }}{\text { Input power }}=\frac{V_S I_S}{V_D I_D}\)

Application of Lenz’s Law in NEET Physics Questions

In a transformer,

\(\frac{N_s}{N_p}=\frac{V_S}{V_D}=\frac{I_p}{I_S}\)

\(\mathbf{k}=\frac{\mathrm{N}_{\mathrm{s}}}{\mathrm{N}_{\mathrm{p}}}\) is called turns ratio.

Energy stored in an inductor is given by,

\(\mathrm{U}=\frac{1}{2} \mathrm{LI}^2\)

Reasons For Energy Loss In A Transformer:

  1. Hysteresis loss.
  2. Loss due to flux leakage
  3. Loss due to resistance of the windings.
  4. Loss due to eddy currents.