NEET Physics Semiconductor Electronics Notes
Semiconductor Electronics
If a p.d. is applied across an intrinsic semiconductor the current I = Ie + Ih
Where Ie is the current due to electrons and I is the current due to holes
- For semiconductors (Eg < 3eV)
- \(\left(\mathrm{E}_{\mathrm{g}}\right)_{\mathrm{Ge}}=0.71 \mathrm{eV},\left(\mathrm{E}_{\mathrm{g}}\right)_{\mathrm{Si}}=1.1 \mathrm{eV}\)
- For insulators, Eg > 3eV
- In an intrinsic semiconductor \(n_e=n_h\)
- In n–type semiconductor \(n_e \gg>n_h\)
- In p–type semiconductor \(n_h \gg n_e\)
- In an extrinsic semiconductor,
- Where ni = intrinsic carrier concentration.
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- In a pn junction,
With of depletion region \(\propto \frac{1}{\text { Doping }}\) - The current gain in the CB mode of a transistor is given by
- The current amplification factor is
- The current gain in CE mode is given by,
NEET Physics Semiconductor Electronics Notes
- The current amplification factor is given by
- w.k.t., IE = Ic + IB
\alpha_{\mathrm{dc}}=\frac{\beta_{\mathrm{dc}}}{\beta_{\mathrm{dc}}+1} \\
\Rightarrow \beta_{\mathrm{dc}}=\frac{\alpha_{\mathrm{de}}}{1-\alpha_{\mathrm{de}}}
\end{array}\)
NEET Physics Semiconductor Electronics Important Formulas
- Voltage gain in an amplifier,
Where RL is loud resistance,
r is the input resistance
\(A_V=-\frac{\beta_{x c} R_L}{r}\)Power gain = \(\mathrm{A}_V \times \mathrm{A}_1\)
\(=A_V \times \beta_x=-\frac{\beta_{x c}^2 R_L}{r}\)OR
\(A_V=\frac{I_C R_o}{I_B R_i}=\beta \frac{R_0}{R_i}\) \(A_P=\beta^2 \frac{R_0}{R_i}\)where Ro and Ri are the output and input resistances respectively.
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Best Short Notes for Semiconductor Electronics NEET
OR Gate
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AND Gate
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Semiconductor Electronics NEET Important Questions and Answers
Note:
- OR gate is equivalent to the parallel switching circuit
- AND gate is equivalent to the series switching circuit
NOT Gate
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NAND Gate
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NEET Study Material for Semiconductor Electronics Chapter
NOR Gate
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NOT Gate Using ‘NAND’ Gate
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Semiconductor Electronics Class 12 NCERT NEET
AND Gate Using NAND Gate
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OR Gate From NAND Gate
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Basic Laws of Boolean Algebra
Boolean Postulates:
0 + A = A
1 . A = A
1 + A = 1
0 . A = 0
\(\mathrm{A}+\overline{\mathrm{A}}=1\)Identify law:
A + A = A, A. A = a
Negation law:
\(\overline{\mathrm{A}}=\mathrm{A}\)PN Junction Diode and Transistors NEET Notes
Commutative law:
A + B = B + A
A . B = B. A
Association law:
(A + B) + C = A + (B + C)
(A. B) . C = A . (B . C)
Distribute law:
A . (B + C) = A . B + A . C