NEET Physics Semiconductor Electronics Notes
Semiconductor Electronics
If a p.d. is applied across an intrinsic semiconductor the current I = Ie + Ih
Where Ie is the current due to electrons and I is the current due to holes
- For semiconductors (Eg < 3eV)
- \(\left(\mathrm{E}_{\mathrm{g}}\right)_{\mathrm{Ge}}=0.71 \mathrm{eV},\left(\mathrm{E}_{\mathrm{g}}\right)_{\mathrm{Si}}=1.1 \mathrm{eV}\)
- For insulators, Eg > 3eV
- In an intrinsic semiconductor \(n_e=n_h\)
- In n–type semiconductor \(n_e \gg>n_h\)
- In p–type semiconductor \(n_h \gg n_e\)
- In an extrinsic semiconductor,
- Where ni = intrinsic carrier concentration.
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- In a pn junction,
With of depletion region \(\propto \frac{1}{\text { Doping }}\) - The current gain in the CB mode of a transistor is given by
- The current amplification factor is
- The current gain in CE mode is given by,
NEET Physics Semiconductor Electronics Notes
- The current amplification factor is given by
- w.k.t., IE = Ic + IB
\alpha_{\mathrm{dc}}=\frac{\beta_{\mathrm{dc}}}{\beta_{\mathrm{dc}}+1} \\
\Rightarrow \beta_{\mathrm{dc}}=\frac{\alpha_{\mathrm{de}}}{1-\alpha_{\mathrm{de}}}
\end{array}\)
NEET Physics Semiconductor Electronics Important Formulas
- Voltage gain in an amplifier,
Where RL is loud resistance,
r is the input resistance
\(A_V=-\frac{\beta_{x c} R_L}{r}\)Power gain = \(\mathrm{A}_V \times \mathrm{A}_1\)
\(=A_V \times \beta_x=-\frac{\beta_{x c}^2 R_L}{r}\)OR
\(A_V=\frac{I_C R_o}{I_B R_i}=\beta \frac{R_0}{R_i}\) \(A_P=\beta^2 \frac{R_0}{R_i}\)where Ro and Ri are the output and input resistances respectively.
Best Short Notes for Semiconductor Electronics NEET
OR Gate
AND Gate
Semiconductor Electronics NEET Important Questions and Answers
Note:
- OR gate is equivalent to the parallel switching circuit
- AND gate is equivalent to the series switching circuit
NOT Gate
NAND Gate
NEET Study Material for Semiconductor Electronics Chapter
NOR Gate
NOT Gate Using ‘NAND’ Gate
Semiconductor Electronics Class 12 NCERT NEET
AND Gate Using NAND Gate
OR Gate From NAND Gate
Basic Laws of Boolean Algebra
Boolean Postulates:
0 + A = A
1 . A = A
1 + A = 1
0 . A = 0
\(\mathrm{A}+\overline{\mathrm{A}}=1\)Identify law:
A + A = A, A. A = a
Negation law:
\(\overline{\mathrm{A}}=\mathrm{A}\)PN Junction Diode and Transistors NEET Notes
Commutative law:
A + B = B + A
A . B = B. A
Association law:
(A + B) + C = A + (B + C)
(A. B) . C = A . (B . C)
Distribute law:
A . (B + C) = A . B + A . C